Optimal. Leaf size=112 \[ \frac{b \text{CannotIntegrate}\left (\frac{\log \left (1-\frac{a+b x}{c+d x}\right )}{(a+b x) \log ^2\left (\frac{a+b x}{c+d x}\right )},x\right )}{b c-a d}-\frac{d \text{CannotIntegrate}\left (\frac{\log \left (1-\frac{a+b x}{c+d x}\right )}{(c+d x) \log ^2\left (\frac{a+b x}{c+d x}\right )},x\right )}{b c-a d} \]
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Rubi [A] time = 0.519287, antiderivative size = 0, normalized size of antiderivative = 0., number of steps used = 0, number of rules used = 0, integrand size = 0, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0., Rules used = {} \[ \int \frac{\log \left (1-\frac{a+b x}{c+d x}\right )}{(a+b x) (c+d x) \log ^2\left (\frac{a+b x}{c+d x}\right )} \, dx \]
Verification is Not applicable to the result.
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Rubi steps
\begin{align*} \int \frac{\log \left (1-\frac{a+b x}{c+d x}\right )}{(a+b x) (c+d x) \log ^2\left (\frac{a+b x}{c+d x}\right )} \, dx &=\int \left (\frac{b \log \left (1-\frac{a+b x}{c+d x}\right )}{(b c-a d) (a+b x) \log ^2\left (\frac{a+b x}{c+d x}\right )}-\frac{d \log \left (1-\frac{a+b x}{c+d x}\right )}{(b c-a d) (c+d x) \log ^2\left (\frac{a+b x}{c+d x}\right )}\right ) \, dx\\ &=\frac{b \int \frac{\log \left (1-\frac{a+b x}{c+d x}\right )}{(a+b x) \log ^2\left (\frac{a+b x}{c+d x}\right )} \, dx}{b c-a d}-\frac{d \int \frac{\log \left (1-\frac{a+b x}{c+d x}\right )}{(c+d x) \log ^2\left (\frac{a+b x}{c+d x}\right )} \, dx}{b c-a d}\\ \end{align*}
Mathematica [A] time = 0.631728, size = 0, normalized size = 0. \[ \int \frac{\log \left (1-\frac{a+b x}{c+d x}\right )}{(a+b x) (c+d x) \log ^2\left (\frac{a+b x}{c+d x}\right )} \, dx \]
Verification is Not applicable to the result.
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Maple [A] time = 1.07, size = 0, normalized size = 0. \begin{align*} \int{\frac{1}{ \left ( bx+a \right ) \left ( dx+c \right ) }\ln \left ( 1+{\frac{-bx-a}{dx+c}} \right ) \left ( \ln \left ({\frac{bx+a}{dx+c}} \right ) \right ) ^{-2}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 0., size = 0, normalized size = 0. \begin{align*} -\frac{\log \left (-{\left (b - d\right )} x - a + c\right ) - \log \left (b x + a\right )}{{\left (b c - a d\right )} \log \left (b x + a\right ) -{\left (b c - a d\right )} \log \left (d x + c\right )} - \int -\frac{1}{{\left ({\left (b d - d^{2}\right )} x^{2} + a c - c^{2} +{\left (b c + a d - 2 \, c d\right )} x\right )} \log \left (b x + a\right ) -{\left ({\left (b d - d^{2}\right )} x^{2} + a c - c^{2} +{\left (b c + a d - 2 \, c d\right )} x\right )} \log \left (d x + c\right )}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{\log \left (-\frac{{\left (b - d\right )} x + a - c}{d x + c}\right )}{{\left (b d x^{2} + a c +{\left (b c + a d\right )} x\right )} \log \left (\frac{b x + a}{d x + c}\right )^{2}}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\log \left (-\frac{b x + a}{d x + c} + 1\right )}{{\left (b x + a\right )}{\left (d x + c\right )} \log \left (\frac{b x + a}{d x + c}\right )^{2}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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